## Problem of the Day #101: Square Roots are Hard
*June 28, 2011*

*Posted by Seungln in : potd , trackback*

If $a = 18.36$, what is the approximate value of $$\sqrt{a^2 \cdot 123456789}$$ Round to the nearest integer. No calculators!

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## Problem of the Day #101: Square Roots are Hard
*June 28, 2011*

*Posted by Seungln in : potd , trackback
*

If $a = 18.36$, what is the approximate value of $$\sqrt{a^2 \cdot 123456789}$$ Round to the nearest integer. No calculators!

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