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Problem of the Day #147: ▲ August 13, 2011

Posted by Sreenath in : potd , trackback

In triangle ABC, $\angle ABC=95^\circ$ and $\angle ACB=50^\circ$. Point P is constructed inside the triangle such that $BP=CP$ and $\frac{[BPC]}{[ABC]}=\frac{1}{5}$. Find the integer closest to $\angle BPC$.

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