## Problem of the Day #320: Algebra 2012
*February 2, 2012*

*Posted by Alex in : potd , trackback*

Find all integer solutions $(x, y)$: $$x^4-y^4 = 2012(2012-2x^2)$$

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## Problem of the Day #320: Algebra 2012
*February 2, 2012*

*Posted by Alex in : potd , trackback
*

Find all integer solutions $(x, y)$: $$x^4-y^4 = 2012(2012-2x^2)$$

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