## Problem of the Day #348: Multiplying Random Numbers
*March 1, 2012*

*Posted by Alex in : potd , trackback*

Albert chooses $6$ random numbers. Each number has a $\frac{1}{2}$ chance of being $2$, a $\frac{1}{3}$ chance of being $3$, and a $\frac{1}{6}$ chance of being $6$. Find the expected value of the product of Albert’s numbers.

## Comments»

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It’s going to be higher than that (the minimum possible product is 2^6).